Spring analogy for flexible structures:
- Bar, fixed in one end, deformation in the other end: k=l33EI
- Bar, supported by two simple supports, deformation in the center: k=l348EI
- Solid axle, deformation by torsion: k=G2lπr4
Equivalent rigidities:
- Spring in series: k=k1+k2k1k2
- Spring in parallel: k=k1+k2
Lagrange’s Equation:
dtd(du˙dT)−dudT+du˙dD+dudU=F
Energies:
T=21mv2;D=21cv2;U=21mu2
Frequencies:
ωn=mk;fn=2π1mk
Damping coefficient:
ζ=ccrc;ccr=2mωn=2km
- Can be measured by comparing amplitudes
- Two consecutive amplitudes: ζ≈2π1lnui+1ui
- N cycles: ζ≈2πN1ln(uk+Nuk)
General solutions:
mu¨+ku=0mu¨+cu˙+ku=0→u(t)=C1cosωnt+C2sinωnt→u(t)=eζωnt(C1cosωdt+C2sinωdt)
- ωd=ωn1−ζ2≈ωn: Damped natural frequency
Fourier’s series:
f(t)f(t)=a0+n=1∑∞(ancosnω0t+bnsinnω0t)=c0+n=1∑∞cncos(nω0t−αn)
Coefficients:
a0=T01∫0T0x(t)dt;an=T02∫0T0x(t)cosnωtdt;bn=T02∫0T0x(t)sinnωtdtcn=an2+bn2;tanαn=anbn
Power spectral density:
⟨x2(t)⟩=T1∫0Tx2(t)dt=a02+211∑∞(an2+bn2)=c02+211∑∞cn2
Data collecting parameters:
Δf=Nfs=T1;Δt=NT=fs1
- Anti-aliasing condition: fs≥fny=2f
- Anti-leakage condition: T0/T∈Z
Modal analysis:
Mu¨+Cu˙+Ku=0
- To obtain natural frequencies:
det(K−ωn2M)=0
- Modal vectors are the eigenvectors of the natural frequencies.
- Modal matrix is:
Φ=[ϕ1,ϕ2,ϕ3]
- Ordered from the lowest resonance frequency to the greatest.
- If a resonance frequency is repeated, additional modal vectors can be obtained by:
ϕiTMϕj=0
Mapping to modal space:
M=ΦTMΦ;η=ΦTu